Unit 1 Lesson 2

The graph is a line: slope and intercept

The graph of \(f(x) = ax + b\) is a straight line. We prove it, name \(a\) the slope and \((0, b)\) the \(y\)-intercept, and learn to read a line off its picture.

Learning Objectives

  • State and justify that the graph of a linear function is a straight line.
  • Identify the slope \(a\) as the rise per unit run, and compute it from two points.
  • Identify the \(y\)-intercept \((0, b)\) and read it off the graph.
  • Sketch a linear function from its slope and intercept, using two points.
  • Relate the sign and size of \(a\) to whether the line rises or falls and how steeply.

From rule to picture

In Lesson 1 we met the linear function \(f(x) = ax + b\) and proved that its rate of change is constant: between any two inputs, the output changes by \(a\) per unit of input. We also saw that \(b = f(0)\).

In the previous course we defined the graph of a function as the set of points \(\bigl(x, f(x)\bigr)\) in the Cartesian plane. So the graph of a linear function is the set

\[G_f = \{\,(x,\, ax + b) \mid x \in \mathbb{R}\,\}.\]

What shape does this set make? The answer is the reason for the name linear: it is a straight line.

The graph of a linear function is a line

Let \(f(x) = ax + b\) with \(a \neq 0\). The graph \(G_f\) is a straight line. Conversely, every line in the plane that is neither vertical nor horizontal is the graph of exactly one linear function.

We use the key fact from Lesson 1: for any two distinct inputs \(x_1 \neq x_2\), the points \(P_1 = (x_1, f(x_1))\) and \(P_2 = (x_2, f(x_2))\) satisfy

\[\frac{f(x_2) - f(x_1)}{x_2 - x_1} = a.\]

Fix two such points \(P_1, P_2\) and let \(\ell\) be the line through them. Take any other graph point \(P = (x_0, f(x_0))\). By the same fact, the ratio of vertical change to horizontal change from \(P_1\) to \(P\) is again \(a\) — the same as from \(P_1\) to \(P_2\). Through a given point, a given ratio of rise to run determines a unique direction, so \(P\) lies on \(\ell\). As \(P\) was an arbitrary point of the graph, every graph point lies on \(\ell\): the graph is contained in a line.

Conversely, the line through \((0, b)\) with rise-to-run ratio \(a\) consists exactly of the points \((x, b + ax)\), which are precisely the points of \(G_f\). So the graph is that line, not merely part of it. A vertical line is excluded because it would assign two outputs to one input (it is not a function), and a horizontal line is excluded because it has \(a = 0\) (a constant function, not first-degree).

Slope and \(y\)-intercept

Now that we know the graph is a line, the two coefficients acquire geometric names.

  • The coefficient \(a\) is the slope of the line. Geometrically it is the rise per unit run: moving one unit to the right (\(\Delta x = 1\)) changes the height by \(a\) (\(\Delta y = a\)). For any two points on the line, \[a = \frac{\Delta y}{\Delta x} = \frac{y_2 - y_1}{x_2 - x_1}.\] This is exactly the rate of change of Lesson 1, now read off the picture.

  • The constant term \(b\) is the \(y\)-intercept: the line crosses the \(y\)-axis at the point \((0, b)\), since \(f(0) = b\).

Reading a line: \(f(x) = 2x - 1\)

Here \(a = 2\) and \(b = -1\). The \(y\)-intercept is \((0, -1)\). The slope \(2\) means: from any point on the line, going \(1\) unit right takes us \(2\) units up. Starting at \((0,-1)\) and applying this once lands at \((1, 1)\).

x y run 1 rise 2 (0, -1) (1, 1)
\(f(x) = 2x - 1\): intercept \((0,-1)\), slope \(2\) (the red triangle).

To plot it we needed only the two blue points; the slope triangle in red shows where the \(2\) comes from.

What the slope tells you at a glance

The sign of \(a\) decides which way the line tilts, and the size of \(|a|\) decides how steeply:

  • \(a > 0\): the line rises from left to right.

  • \(a < 0\): the line falls from left to right.

  • The larger \(|a|\) is, the steeper the line; a small \(|a|\) gives a gentle slope.

The intercept \(b\) does something different: changing \(b\) slides the whole line straight up or down without changing its tilt. Two linear functions with the same \(a\) have parallel graphs.

x y
\(a > 0\): rises
x y
\(a < 0\): falls

How to sketch any linear function

Because two points determine a line, sketching \(f(x) = ax + b\) takes only two steps:

  1. Plot the \(y\)-intercept \((0, b)\).

  2. Use the slope to step to a second point — go \(1\) right and \(a\) up (down if \(a < 0\)) — then draw the line through both.

When \(b = 0\) the function is the direct proportionality \(f(x) = ax\), whose line passes through the origin \((0,0)\); the slope alone then fixes it.

Connection to Computer Science

Drawing a straight segment between two points is one of the most basic operations a graphics program performs, and it rests on exactly this idea: once you know a starting point and a constant step (the slope), every further point is reached by repeating the same small move. The same constant-step reasoning lets a program fill in intermediate values between two known data points — moving in equal increments along a line.

Is every straight line such a graph?

It is tempting to say "linear function" and "straight line" are the same thing. They are not quite. Two families of lines are left out.

A vertical line, like \(x = 3\), is not the graph of any function at all: the input \(3\) would have infinitely many outputs, violating the uniqueness condition in the definition of a function. (This is the "vertical line test" from the previous course.)

A horizontal line, like \(y = 3\), is a function, but a constant one — its slope is \(0\), so it fails the requirement \(a \neq 0\) and is not first-degree.

So the graphs of linear functions are exactly the lines that are neither vertical nor horizontal: the genuinely slanted lines. That is what the converse half of our theorem said.

Exercises

Exercise 1

Consider \(f \colon \mathbb{R} \to \mathbb{R},\; f(x) = 3x - 2\).

a)

b)

c)

Exercise 2

For each described line, choose the signs of the slope \(a\) and intercept \(b\).

a)

A line that falls from left to right and crosses the \(y\)-axis above the origin.

Signs of \(a\) and \(b\)?

b)

A line that rises from left to right and passes through the origin.

Signs of \(a\) and \(b\)?

Exercise 3

Decide whether each statement about graphs of linear functions is true or false.

a)

The graph of \(f(x) = ax\) (with \(b = 0\)) passes through the origin.

b)

Two linear functions with the same slope \(a\) have parallel graphs.

c)

Increasing the value of \(b\) tilts the line more steeply.

d)

A vertical line is the graph of some linear function.

Exercise 4

A line is the graph of a linear function and passes through \((0, 3)\) and \((2, 7)\). Find its slope and intercept.

a)

b)

Exercise 5

From the slope, decide whether each line rises or falls from left to right.

a)

\(f(x) = 2x - 1\)

b)

\(f(x) = -3x + 2\)

c)

\(f(x) = x\)

d)

\(f(x) = 5 - x\)

e)

\(f(x) = \tfrac{1}{2}x - 4\)

Summary

  • The graph of a linear function \(f(x) = ax + b\) is a straight line; conversely, every slanted (non-vertical, non-horizontal) line is the graph of exactly one linear function.

  • The slope \(a\) is the rise per unit run, \(a = \dfrac{\Delta y}{\Delta x}\) — the Lesson 1 rate of change, read off the picture. The \(y\)-intercept is \((0, b)\).

  • \(a > 0\) rises, \(a < 0\) falls, and larger \(|a|\) is steeper; changing \(b\) slides the line vertically. Equal slopes give parallel lines.

  • To sketch a line: plot \((0, b)\), step \(1\) right and \(a\) up to a second point, and draw through both. If \(b = 0\) the line passes through the origin.